tag:blogger.com,1999:blog-2787161678592839240.post8609778440139210250..comments2024-03-29T12:30:29.739+05:30Comments on www.mathsblog.in : Maths Blog for School Teachers & Students: കോണിസ്ബെര്ഗ് പാലങ്ങള് - ഒരു സമസ്യവി.കെ. നിസാര്http://www.blogger.com/profile/14303804236214732024noreply@blogger.comBlogger89125tag:blogger.com,1999:blog-2787161678592839240.post-80905047033766372412010-05-03T13:26:01.593+05:302010-05-03T13:26:01.593+05:30CONGRATULATIONS AMMU<b>CONGRATULATIONS AMMU</b>AZEEZhttps://www.blogger.com/profile/07062507383328017955noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-5000238239166765002010-05-03T13:24:52.305+05:302010-05-03T13:24:52.305+05:30This comment has been removed by the author.AZEEZhttps://www.blogger.com/profile/07062507383328017955noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-53290507314722171722010-05-03T12:59:36.014+05:302010-05-03T12:59:36.014+05:30FULL A+ AMMU
CONGRATULATIONSFULL A+ AMMU<br /><br />CONGRATULATIONSbhamahttps://www.blogger.com/profile/04270776567671430504noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-23258200396810628532010-05-03T12:35:49.928+05:302010-05-03T12:35:49.928+05:30This comment has been removed by the author.AZEEZhttps://www.blogger.com/profile/07062507383328017955noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-82751499709414688932010-05-03T12:35:12.481+05:302010-05-03T12:35:12.481+05:30FULL A+ AMMU
CONGRATULATIONSFULL A+ AMMU<br /><br />CONGRATULATIONSghssperingottukarahttps://www.blogger.com/profile/13953847444512649968noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-34277724288316798162010-05-03T12:10:34.467+05:302010-05-03T12:10:34.467+05:30Ammu full A+Ammu full A+വി.കെ. നിസാര്https://www.blogger.com/profile/14303804236214732024noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-72822727521847935512010-05-03T08:32:05.122+05:302010-05-03T08:32:05.122+05:30@ammu,gayathri
967*307=296869.(967 and 307 are two...@ammu,gayathri<br />967*307=296869.(967 and 307 are two prime numbers.<br />2 represents both of u.<br />the remaining digits 96869 is palindrome.<br />cool down till 12.01vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-40627367792498189722010-05-03T07:49:06.429+05:302010-05-03T07:49:06.429+05:30@ Maths blog team
എന്റെ രജിസ്റ്റര് നമ്പര് ആണ് ...@ Maths blog team <br /><br />എന്റെ രജിസ്റ്റര് നമ്പര് ആണ് 296869 .റിസള്ട്ട് അറിഞ്ഞാല് ഇവിടെ പബ്ലിഷ് ചെയണം .<br /><br />Vismaya (Ammu)Ammuhttps://www.blogger.com/profile/01909564563673726003noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-73879185973428033542010-05-01T11:51:41.283+05:302010-05-01T11:51:41.283+05:30This comment has been removed by the author.ഗായത്രിhttps://www.blogger.com/profile/07529110968769165999noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-25315378819620668162010-05-01T11:47:24.862+05:302010-05-01T11:47:24.862+05:30Here u can mak a semicircle with radius 10 M with ...Here u can mak a semicircle with radius 10 M with the three sectors.<br /><br />So total area =3.14*50=157 M ^2AZEEZhttps://www.blogger.com/profile/07062507383328017955noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-77132776818522205612010-05-01T11:29:13.173+05:302010-05-01T11:29:13.173+05:30Area of the sector = π r^2 x/360
Here r =10m and...Area of the sector = π r^2 x/360<br /><br />Here r =10m and x=1800 <br /><br />Total area available to the three horses to graze <br />= 3.14 * 10 * 10 * 180 / 360 <br /> = 3.14 * 100 * ½ <br /> = 3.14 * 50 = 157 m^2ഗായത്രിhttps://www.blogger.com/profile/07529110968769165999noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-16033839822695666522010-05-01T03:30:49.414+05:302010-05-01T03:30:49.414+05:30yeah.
the problem had a diagram showing that the ...yeah.<br /><br />the problem had a diagram showing that the sides were long enough.<br /><br />i was too lazy to draw one.Anoophttps://www.blogger.com/profile/16516943524664893937noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-25044837197689525242010-05-01T03:22:59.727+05:302010-05-01T03:22:59.727+05:30If any side is less than 20m, the sectors will ove...If any side is less than 20m, the sectors will overlap and the problem will become more complicated.Umesh::ഉമേഷ്https://www.blogger.com/profile/06474085260183409502noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-3328165308224541202010-05-01T03:20:24.375+05:302010-05-01T03:20:24.375+05:30A similar problem was asked in my class X board ex...A similar problem was asked in my class X board exams(2001). <br /><br />They didn't provide the dimensions of the sides, which made it sort of easier. <br /><br />I guess it becomes a bit more confusing if one throws in some additional(useless) info like dimensions, angles, etc. :)Anoophttps://www.blogger.com/profile/16516943524664893937noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-91834653338362123752010-05-01T03:19:09.487+05:302010-05-01T03:19:09.487+05:30Nice question. People may try to compute the angl...Nice question. People may try to compute the angles using the cosine formula, find the areas and then add them :)Umesh::ഉമേഷ്https://www.blogger.com/profile/06474085260183409502noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-85184170622149070992010-05-01T03:08:08.907+05:302010-05-01T03:08:08.907+05:30Let α, β, γ be the three angles in radians. We ne...Let α, β, γ be the three angles in radians. We need not find these angles. The first horse can graze (1/2) x 10 x 10 x α = 50α. Similar case with the other horses.<br /><br />Since these three areas do not overlap, the total area is the sum of these, which is <br /><br />50α + 50β + 50γ = 50(α + β + γ) = 50π<br /><br />since α + β + γ = π.<br /><br />The answer is 50π.Umesh::ഉമേഷ്https://www.blogger.com/profile/06474085260183409502noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-84564039385874506252010-05-01T03:03:34.865+05:302010-05-01T03:03:34.865+05:30yep .. :)
i'm guessing it was a one-step pro...yep .. :)<br /><br />i'm guessing it was a one-step problem for you.Anoophttps://www.blogger.com/profile/16516943524664893937noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-5213476301485855552010-05-01T02:50:51.112+05:302010-05-01T02:50:51.112+05:3050π ?50π ?Umesh::ഉമേഷ്https://www.blogger.com/profile/06474085260183409502noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-54461065380188129212010-04-30T23:23:31.613+05:302010-04-30T23:23:31.613+05:30Question:
Consider a triangular field ABC of sid...Question: <br /><br />Consider a triangular field ABC of sides AB=100m, BC=120m, AC=125 m. <br /><br />To a pole at each vertex A,B,C, a horse is tethered, with a rope of length 10m.<br /><br />Find the total area available to the three horses to graze.Anoophttps://www.blogger.com/profile/16516943524664893937noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-54325393357181573782010-04-29T19:06:24.131+05:302010-04-29T19:06:24.131+05:30@anoop sir,
without using trig.relations there is ...@anoop sir,<br />without using trig.relations there is simple solutions. tryvijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-12062002508254906892010-04-29T16:19:55.324+05:302010-04-29T16:19:55.324+05:30@ vijayan sir
"In a regular nonagon ABCDEFGH...@ vijayan sir<br /><br />"In a regular nonagon ABCDEFGHI ,show that AF=AB+AC"<br /><br />We can generalize the problem.<br /><br />Any diagonal of an N-sided regular polygon A_1A_2...A_N, can be obtained as:<br /><br />A_iA_j = 2R * sin[(j-i)*180/N], <br /><br />where R is the circumradius, and the angle is in degrees.<br /><br />(R, in turn, can be obtained by putting <br />j-i =1 <br />and <br />A_iA_j = length of the sides <br />in the equation above)<br /><br />AF = 2R sin (100)<br />AB = 2R sin (20)<br />AC = 2R sin(40)<br /><br />Using trigonometric identities, it can be shown that AF=AB+AC.<br /><br />[sin X + sin Y = 2 * sin((X+Y)/2)* cos((X-Y)/2)]<br /><br />There should be alternate solutions, without using trig. identities.Anoophttps://www.blogger.com/profile/16516943524664893937noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-54760566914238517102010-04-29T08:11:28.777+05:302010-04-29T08:11:28.777+05:30@gayathri,
the reg.no. is a multiple of two,three ...@gayathri,<br />the reg.no. is a multiple of two,three digit prime numbers.one is 967.( the only divisors of that reg.number)VIJAYAN N Mhttps://www.blogger.com/profile/01196709026427033192noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-41071356106556439002010-04-28T22:33:59.637+05:302010-04-28T22:33:59.637+05:30@gayathri&ammu
the first digit represents both...@gayathri&ammu<br />the first digit represents both of you.the remaining integer of 5 numbers is a palindrome number .<br />more over that integer can be read if we write it in inverse order.<br />the number denotes first,fourth,sixth digit is a pefect square .second and third is a part of a perfect square.lllly fifth and sixth another part of a perfect square<br />am i rt?<br />then wait till the time that i mentioned. ok keep it up.vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-31875459033263963342010-04-28T21:13:15.560+05:302010-04-28T21:13:15.560+05:30വിജയന് സര് / ഹരി സര്
@Ammu, don't afraid ...വിജയന് സര് / ഹരി സര് <br /><br />@Ammu, don't afraid of result.it will take its own time.<br />before that you don't reveal your reg.no.you send a qn. which has the answer,that is your number.<br />let the viewers calculate .your reg.no.<br />blog will arrange steps to view the results on time.PL COOL DOWN TILL MAY 1ST WEEK.<br /><br /><br />എന്റെ രജിസ്റ്റര് നമ്പറിനെ കുറിച്ച് ഞാന് ഒരു പസില് കൊടുത്തിട്ടുണ്ട് . നോക്കിയിരിക്കുമെന്നു കരുതുന്നു. ഉത്തരം കിട്ടി കാണുമെന്നും കരുതുന്നു.ഗായത്രിhttps://www.blogger.com/profile/07529110968769165999noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-2144835193683017112010-04-27T21:32:27.502+05:302010-04-27T21:32:27.502+05:30@ Vijayan sir
My register number is a six digit...@ Vijayan sir <br /><br /><b> My register number is a six digit number of the form ABCDCB . Sum of the digits is 40 also A+B=11 ,C+D=14 and B+D=17.Find my register number ? </b><br /><br /><b> Vismaya </b>ഗായത്രിhttps://www.blogger.com/profile/07529110968769165999noreply@blogger.com