tag:blogger.com,1999:blog-2787161678592839240.post542584390492819270..comments2024-03-29T12:30:29.739+05:30Comments on www.mathsblog.in : Maths Blog for School Teachers & Students: SSLC റിവിഷന് - രേഖീയ സംഖ്യകള്വി.കെ. നിസാര്http://www.blogger.com/profile/14303804236214732024noreply@blogger.comBlogger44125tag:blogger.com,1999:blog-2787161678592839240.post-82081991296830027562010-01-29T22:59:12.976+05:302010-01-29T22:59:12.976+05:30Sir,My question is regarding no.96 in your 100 que...Sir,My question is regarding no.96 in your 100 questions.is it necessary to give any additinal information in that question<br />96.<br />ഒോര െപാകമള രണ െകടിെങള ഒര ൈമതാനതിെെ രണറതമണ്. ൈമതാനതിെെ ഒര<br />സാനതനിന ോനാകോോാള അവയെെ മകളറം 60˚, 30˚എനീ ോമലോകാണകളില കാണന. ഓോരാ<br />െകടിെതിനം എത െപാകമണ്? ോനാകന സാനം നിരണയികക.sajihttps://www.blogger.com/profile/12694705623376103242noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-75225030770023812872010-01-29T22:49:17.908+05:302010-01-29T22:49:17.908+05:30Dear Saji
Please correct it as 2 and 1/30
Kindly g...Dear Saji<br />Please correct it as 2 and 1/30<br />Kindly go through the comments below that post. I think some other corrections are also made in the commentsJOHN P Ahttps://www.blogger.com/profile/02064365401403870252noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-31997771004438037212010-01-29T22:09:14.473+05:302010-01-29T22:09:14.473+05:30Sir
96.
ഒോര െപാകമള രണ െകടിെങള ഒര ൈമതാനതിെെ രണറതമണ്...Sir<br />96.<br />ഒോര െപാകമള രണ െകടിെങള ഒര ൈമതാനതിെെ രണറതമണ്. ൈമതാനതിെെ ഒര<br />സാനതനിന ോനാകോോാള അവയെെ മകളറം 60˚, 30˚എനീ ോമലോകാണകളില കാണന. ഓോരാ<br />െകടിെതിനം എത െപാകമണ്? ോനാകന സാനം നിരണയികക.<br /> please make sure that this question is correct?sajihttps://www.blogger.com/profile/12694705623376103242noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-44987347251146005402010-01-29T22:06:33.779+05:302010-01-29T22:06:33.779+05:30Sir,
51) ഒര സംഖയയെെയം അതിെെ വയലകമതിെെയം തക 20 1/30...Sir,<br />51) ഒര സംഖയയെെയം അതിെെ വയലകമതിെെയം തക 20 1/30 (20&1/30) ആയാല സംഖയ<br />കാണക<br /> is above question has a perfect answer<br />Please give the answer also<br />SAJIKUMAR Psajihttps://www.blogger.com/profile/12694705623376103242noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-47061080946106896842010-01-29T22:03:05.554+05:302010-01-29T22:03:05.554+05:30Sir,Can u give the correctnees of
ഒോര െപാകമള രണ െ...Sir,Can u give the correctnees of<br /> ഒോര െപാകമള രണ െകടിെങള ഒര ൈമതാനതിെെ രണറതമണ്. ൈമതാനതിെെ ഒര<br />സാനതനിന ോനാകോോാള അവയെെ മകളറം 60˚, 30˚എനീ ോമലോകാണകളില കാണന. ഓോരാ<br />െകടിെതിനം എത െപാകമണ്? ോനാകന സാനം നിരണയികക.<br />and please give some hints<br />SAJIKUMARsajihttps://www.blogger.com/profile/12694705623376103242noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-32867386685552110272010-01-29T22:01:38.065+05:302010-01-29T22:01:38.065+05:30@ Vijayan Sir
Really I never go through that value...@ Vijayan Sir<br /><b>Really I never go through that value sir .It’s my mistake.</b><br /><b>Thanks to point out my mistake </b><br /><b>Really it is a big mistake.I know… I am sorry sir</b><br /><b>Once again thanks to Vijayan sir & Jessy Sir to point out mistake .</b>ശ്രീകുമാര്https://www.blogger.com/profile/05137813013128024794noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-60118942593898578162010-01-29T21:48:40.461+05:302010-01-29T21:48:40.461+05:30four terms in AP:
@kannan sir,perhaps you may went...four terms in AP:<br />@kannan sir,perhaps you may went through the comment of jessy at 8.16/29.01.10<br />so shall i add one thing in your solution regardig four terms in AP.<br />X=16.77 IS ADMISSIBLE<br />then the terms are "-8.3,-.1,+8.1,+16.3" if we take sqroot (151/9) is 4.1.<br />here the correct value of d=sqroot(151/9).<br />then the product is 105 AND THE SUM IS 16.vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-64876175579099897282010-01-29T19:48:59.706+05:302010-01-29T19:48:59.706+05:30തൃശ്ശൂരില് ഇപ്പോള് മാത്സ് ക്ലാസ്റ്റര് ആണ്. എസ,എ...തൃശ്ശൂരില് ഇപ്പോള് മാത്സ് ക്ലാസ്റ്റര് ആണ്. എസ,എച് സി ജി എച് എസ് എസ്സില് . ബ്ലോഗ് പരിചയപ്പെടലാണ്.<br />പക്ഷെ അവിടത്തെ എച്. എം ലാബ് തരില്ലെന്ന്. !!!!!!!!ഇങ്ങനെയും എച്.എമോgeetha ramhttps://www.blogger.com/profile/17139955641291019408noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-66478543910919988572010-01-28T07:25:32.135+05:302010-01-28T07:25:32.135+05:30DEAR MURALISIR,JOHN SIR,AZEES,
ABOUT TRIANGLE;
yo...DEAR MURALISIR,JOHN SIR,AZEES,<br />ABOUT TRIANGLE;<br />you are travelling in same boat and sitting in different places.your destination is same.(am i right?)<br />the area of 25,25,30&25,25,40 are same.so many examples.since 30,40,50 a rt triangle we get the result.<br />17,17,16&17,17,30 have the same area 120 .both are isoceles and part of same rt triangle 34,30,16.<br />take any rt triangle,divide it into two parts,the area is same and it will be isoceles( geometric proof: take a rt triangle.draw a semicircle with radius half of hyp.and the mid point of hyp. as centre. the area of the two triangles will be same.<br />so i am getting down from the boat.vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-5960761345330342592010-01-28T05:51:24.708+05:302010-01-28T05:51:24.708+05:30This comment has been removed by the author.JOHN P Ahttps://www.blogger.com/profile/02064365401403870252noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-85357980115998762372010-01-28T05:51:21.396+05:302010-01-28T05:51:21.396+05:30സമപാര്ശ്വത്രികോണങ്ങളെ തുല്യവിസ്തീണ്ണമുള്ള ജോടികളാ...സമപാര്ശ്വത്രികോണങ്ങളെ തുല്യവിസ്തീണ്ണമുള്ള ജോടികളായി കാണാം.ഈ അഭിപ്രായത്തോട് പ്രതികരിക്കുകJOHN P Ahttps://www.blogger.com/profile/02064365401403870252noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-30081558350976567592010-01-28T00:04:53.056+05:302010-01-28T00:04:53.056+05:3025, 25 30 triangle is the sum of 2 rht. triangle w...25, 25 30 triangle is the sum of 2 rht. triangle whose sides are 25, 15 2o ( if these triangles joins with the side 20 we get 25 25 30 triangle)<br />lllrly 25, 25 40 triangle is the sum of 2 rht. triangle whose sides are 25, 15 2o (if these triangles joins with the side 15 we get 25 25 40 triangle)<br />Also If we join 2 rht. triangles whose sides are 5 12 13 with the side 5 we get 13,13 24 triangle<br />If we join 2 rht. triangles whose sides are 5 12 13 with the side 12 we get 13 13 10 traingle<br />ie area same perimeter differentMURALEEDHARAN.C.Rhttps://www.blogger.com/profile/12387715646323771032noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-21189069790602086682010-01-27T18:26:30.566+05:302010-01-27T18:26:30.566+05:30The area of triangles with sides 25,25,30 & 25...The area of triangles with sides 25,25,30 & 25,25,40 are same.perhaps you may wonder. many are in the list(perimeter different and area same). make a list of such triangles and find out any specialityvijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-13877406995889633172010-01-27T13:19:58.249+05:302010-01-27T13:19:58.249+05:30@ Azeez sir
Most probably it is because the heig...<b>@ Azeez sir </b><br /><b>Most probably it is because the height will decrease if we increase a side that’s why the area decreases </b><br /><b>Mostly this is because an obtuse angled triangle will be formed.</b><br /><br /><b> I AM NOT VERY MUCH SURE ABOUT THE ANSWER . </b><br /><b> Is it correct or not ? </b>ശ്രീകുമാര്https://www.blogger.com/profile/05137813013128024794noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-34456167790665983272010-01-27T09:57:27.460+05:302010-01-27T09:57:27.460+05:30The area of the triangle with sides 205,188 and 85...The area of the triangle with sides 205,188 and 85 is GREATER THAN the area of the triangle with sides 225,188 and 85, Even though here one side is larger. WHY?AZEEZhttps://www.blogger.com/profile/07062507383328017955noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-25050281148759218272010-01-27T07:16:10.339+05:302010-01-27T07:16:10.339+05:30@kannan sir,bhama:
i wonder how did you get enough...@kannan sir,bhama:<br />i wonder how did you get enough time to go through the qns. <br />thank you.vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-45708124692172613432010-01-27T06:12:56.071+05:302010-01-27T06:12:56.071+05:30നിസാര് സാര്.
ഞാന് ശ്രമിക്കാം.ഏതാനും T M മാത്യക ...നിസാര് സാര്.<br />ഞാന് ശ്രമിക്കാം.ഏതാനും T M മാത്യക തയ്യാറാക്കട്ടെ.JOHN P Ahttps://www.blogger.com/profile/02064365401403870252noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-56713934118474645682010-01-26T22:01:27.974+05:302010-01-26T22:01:27.974+05:30എങ്ങിനെ ഒരു ആവറേജ് കുട്ടിക്ക് അംശബന്ധവും അനുപാതവും...<b>എങ്ങിനെ ഒരു ആവറേജ് കുട്ടിക്ക് അംശബന്ധവും അനുപാതവും പഠിപ്പിക്കാമെന്ന് ആരെങ്കിലും വിശദീകരിക്കാമോ?</b>വി.കെ. നിസാര്https://www.blogger.com/profile/14303804236214732024noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-771967679313701322010-01-26T21:41:45.450+05:302010-01-26T21:41:45.450+05:30ജോണ് സര് നാലു പട്ടണങ്ങളുടെ ഉത്തരം നോക്കിയോ .നല്ല...ജോണ് സര് നാലു പട്ടണങ്ങളുടെ ഉത്തരം നോക്കിയോ .നല്ല രസമുള്ള ചോത്യം ആയിരുന്നു അത് .ഉത്തരം കിട്ടുന്ന വരെ നല്ല ത്രില് ഉണ്ടാക്കിയ ച്യോത്യം <br /><br /><b>Is my answer correct or not</b><br /><b>Actually bhama teacher's answer guided me to get my answer </b><br /><br /><b>If my answer is correct<br />50% Credit to Bhama teacher also</b><br /><b>50% Credit to the clue from John sir (The question is based on Trignometry )</b>ശ്രീകുമാര്https://www.blogger.com/profile/05137813013128024794noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-62936952839724823372010-01-26T21:33:30.202+05:302010-01-26T21:33:30.202+05:30The sides of the right triangles are (6,8,10) &...The sides of the right triangles are (6,8,10) & (5,12,13)bhamahttps://www.blogger.com/profile/04270776567671430504noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-38400723230632150282010-01-26T21:23:25.107+05:302010-01-26T21:23:25.107+05:30@Vijayan Sir
Let the base of right angled triangle...@Vijayan Sir<br /><b>Let the base of right angled triangle be ‘b’ , altitude ‘a ‘ and hypotenuse ‘c’<br />Then by Pythagorean theorem c = (a^2 + b^2)^1/2</b><br /><br /><b>The right triangles have perimeter P = a + b + c = a + b + (a^2 + b^2)^1/2<br />and area A = a b / 2. </b><br /><br /><b> ab - 2a - 2b = 2 (a^2 + b^2)^1/2 or (ab - 2a - 2b)^2 = 4(a^2 + b^2). </b><br /><b>Simplifying the sides of the first right triangle are 6,8,10</b><br /><b>AREA = PERIMETER = 24 </b><br /><br /><b>In the Same way sides of second right angled triangle are5,12,13 </b><br /><b> AREA = PERIMETER = 30. </b><br /><br /><b>The others have perimeter P = a + b + c THEN, area A = [s(s-a)(s-b)(s-c)] ^1/2 </b><br /><b>S= P / 2. </b><br /><b>On solving </b><br /><b>a=b=c=100 reveals the sides of the first triangle are 5,5,8, Area = 12 , Perimeter = 18 </b><br /><b>The sides of the second triangle are 3,25,26 .practically it is a small angles triangle Area = 36 , Perimeter = 54</b><br /><br />1)For right angled triangle<br />Area =Perimeter = 24<br />2)For Second right angled triangle<br />Area =Perimeter = 30<br /><br />For other triangles<br />1)Area=12 and Perimeter = 18<br />2)Area=36,Perimeter = 54ശ്രീകുമാര്https://www.blogger.com/profile/05137813013128024794noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-50904776873326236992010-01-26T21:03:59.281+05:302010-01-26T21:03:59.281+05:30Freedom in Mind,
Faith in Words,
Pride in our
Hear...Freedom in Mind,<br />Faith in Words,<br />Pride in our<br />Heart,<br />Memories in our Souls.<br />Lets Salute the Nation on<br />REPUBLIC DAY...VIJAYAN N Mhttps://www.blogger.com/profile/01196709026427033192noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-71921248963864509252010-01-26T20:59:38.470+05:302010-01-26T20:59:38.470+05:30I drew 4 triangles with integer sides .two were ri...I drew 4 triangles with integer sides .two were right and two were not.the right ones had area numerically equal to there perimeter,<br />and the others areas were two thirds of their perimeters . what were the sides ,perimeters and areas of 4 triangles?vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-2963473850902583642010-01-26T20:42:28.137+05:302010-01-26T20:42:28.137+05:30e,n,t,e,t,t,f,f,s,s,e,n,t,e,t,t,f,f,s,s,vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-6357555792429340752010-01-26T20:41:11.341+05:302010-01-26T20:41:11.341+05:30These are the first letters of One,Two,Three,Four,...<b>These are the first letters of One,Two,Three,Four,Five,Six,Seven....</b>.<br /><br />So next letter is e represents Eight<br /><br /><b>o,t,t,f,f,s,s,e,......</b><br /><br />Isn't it Muraleedharan sirശ്രീകുമാര്https://www.blogger.com/profile/05137813013128024794noreply@blogger.com