tag:blogger.com,1999:blog-2787161678592839240.post2588699667794298503..comments2024-03-28T15:06:26.752+05:30Comments on www.mathsblog.in : Maths Blog for School Teachers & Students: A Lion's contribution to a noble cause!വി.കെ. നിസാര്http://www.blogger.com/profile/14303804236214732024noreply@blogger.comBlogger12125tag:blogger.com,1999:blog-2787161678592839240.post-38433803078924357752009-11-05T23:22:00.700+05:302009-11-05T23:22:00.700+05:30hai,
i'm very happy to watch&learn the mat...hai,<br />i'm very happy to watch&learn the maths blog. thanks a lot for all the trssreevalsamhttps://www.blogger.com/profile/00239833908447645398noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-10093069930284405192009-10-15T16:54:45.979+05:302009-10-15T16:54:45.979+05:30my student AMRUTHA checked the same case with anot...my student AMRUTHA checked the same case with another polinomial<br /><br />"if (x-2)&(x-5) are two factors of a polinomial 'X cubed-aXsqured-bX+20',<br />find the value of 'a'&'b'.in this polinomial you won't get any value of 'a'&'b'. can you find using one equation? YOUR answer will be NO.<br />THEN think ......"vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-9540016117605678572009-10-15T16:53:51.948+05:302009-10-15T16:53:51.948+05:30my student AMRUTHA checked the same case with anot...my student AMRUTHA checked the same case with another polinomial<br /><br />"if (x-2)&(x-5) are two factors of a polinomial 'X cubed-aXsqured-bX+20',<br />find the value of 'a'&'b'.in this polinomial you won't get any value of 'a'&'b'. can you find using one equation? YOUR answer will be NO.<br />THEN think ......"vijayanhttps://www.blogger.com/profile/02345885159669791726noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-29775473216611254672009-10-15T11:38:15.306+05:302009-10-15T11:38:15.306+05:3054+9P+3Q+9=-54+9P-3Q+9
Since both sides of the eqn...54+9P+3Q+9=-54+9P-3Q+9<br />Since both sides of the eqn is equal to zero,<br />54+9p+3q+9=-1*(-54+9P-3Q+9)<br /> =54-9P+3Q-9<br />9P+9=-9P-9<br />18P=-18<br />P=-1<br />MURALEEDHARAN.C.R<br />GVHSS VATTENADMURALEEDHARAN.C.Rhttps://www.blogger.com/profile/12387715646323771032noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-57657520703263152392009-10-14T08:14:28.077+05:302009-10-14T08:14:28.077+05:30amruthas words" don't use other variable ...amruthas words" don't use other variable like K.dont use two equations to solve. I know the answers.<br />I want genuine reason.<br />there are so many possibiliteis ,if we take another polinimial, without even getting the value of P aswellas Q " ...VIJAYAN N Mhttps://www.blogger.com/profile/01196709026427033192noreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-84025039299883204152009-10-14T06:03:59.226+05:302009-10-14T06:03:59.226+05:30നന്ദി അഹല് ജോഷ,
തെറ്റ് തിരുത്തിയിട്ടുണ്ട്.
പണ്ട് ...നന്ദി അഹല് ജോഷ,<br />തെറ്റ് തിരുത്തിയിട്ടുണ്ട്.<br />പണ്ട് രാജാവ് നഗ്നനാണെന്നുറക്കെ ആദ്യം വിളിച്ചുപറഞ്ഞതും, ഒരു കുട്ടിയായിരുന്നു!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-47061879495752980742009-10-13T21:40:53.478+05:302009-10-13T21:40:53.478+05:30Let,
K=0
-15+3p-q= k + 21+3p+q= k
3p-...Let,<br /> K=0<br />-15+3p-q= k + 21+3p+q= k<br />3p-q=k+15 + 3p+q=k-21<br />6p=2k-6<br />p = (2k-6)/6<br />p =2k-1<br /> k=0 <br />So P= -1<br /><br />Ahal josha J.S<br />X th Std<br />GVHSS MEPPAYURAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-51123372758992274332009-10-13T21:24:22.175+05:302009-10-13T21:24:22.175+05:30I found that there is a mistake in the English tra...I found that there is a mistake in the English translation of the problem related with polynomials.<br />If P and Q are two…..<br />Change it as<br />If (x+3) and (x-3) are two ….<br /><br />AHAL JOSHA J.S.<br />GVHSS MEPPAYUR (X th Std.)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-28132414948543343852009-10-13T18:17:30.321+05:302009-10-13T18:17:30.321+05:3054+9p+3q+9=-54+9p-3q+9=k say
63+9p+3q=k and -45+9p...54+9p+3q+9=-54+9p-3q+9=k say<br />63+9p+3q=k and -45+9p-3q=k<br />9p+3q=k-63 and 9p-3q=k+45<br />substracting eqn 2 from eqn 1 we get 6q=-108 ie q=-18<br />adding these two eqns we get 18p=2k-18<br />ie p=(k-9)/9<br />but k=0<br />p=-1<br />Rajan<br />KUNNAMKULAMAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-9155818284587447132009-10-13T16:25:40.530+05:302009-10-13T16:25:40.530+05:30The eqn. 54+9P+3Q+9=-54+9P-3Q+9
is only one eqn.
...The eqn. 54+9P+3Q+9=-54+9P-3Q+9<br />is only one eqn.<br /> And "Amritha" try to find the value of two variables using only one eqn.<br />first she find the value of Q and put the same value in the same eqn.<br /><br />I Think this is the problem arise here.AZEEZnoreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-71337373452513670962009-10-13T11:20:23.131+05:302009-10-13T11:20:23.131+05:30p(3)=0 implies 3p+q=-21
p(-3)=0 implies 3p-q=15
3...p(3)=0 implies 3p+q=-21<br />p(-3)=0 implies 3p-q=15<br />3p=(15+-21)/2<br /> ie 3p=-6/2<br />3p =-3<br />p =-1<br /><br /><br />MURALEEDHARAN.C.R<br />GVHSS VATTENADAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2787161678592839240.post-18053918648869473672009-10-13T06:33:01.403+05:302009-10-13T06:33:01.403+05:30This is an interesting mathematical situation.
Act...This is an interesting mathematical situation.<br />Actually Amiritha Mohan or the person who purposefully force her to think so for an intellectual purpose, wrote the first step as 0 = 0<br />It was harmless because of the homogeneity of the basic equations.The cubes on both sides provide answer to Q<br />But unfortunately the equation gave up odd powers after substitution of the value of Q.Naturally infinite consistency occurs.<br />Ihis is common in solving equations by Cramer method.<br />I am helpless to help Amirtha because this is the general nature of equationsJOHN P Anoreply@blogger.com